X2 3x 3 2 X 1 X 2 7 Web 3x 2 2x 1 3 left x 1 right times left frac 3x 1 3 right Add frac 1 3 to x by finding a common denominator and adding the numerators Then reduce the fraction to lowest terms if possible
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X2 3x 3 2 X 1 X 2 7
X2 3x 3 2 X 1 X 2 7
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Web 1 1 x3 x 3 3x2 3 x 2 3x 3 x 2 2 Divide the highest order term in the dividend x3 x 3 by the highest order term in divisor x2 x 2 Multiply the new quotient term by the divisor The expression needs to be subtracted from the dividend so change all
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X2 3x 3 2 X 1 X 2 7

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Web Solve an equation inequality or a system Example 2x 1 y 2y 3 x

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Web Limits x 3lim x2 2x 3x2 9 Solve your math problems using our free math solver with step by step solutions Our math solver supports basic math pre algebra algebra trigonometry calculus and more

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Web Differentiation dxd x 5 3x2 2 Integration 01 xe x2dx Limits x 3lim x2 2x 3x2 9 Solve your math problems using our free math solver with step by step solutions Our math solver supports basic math pre algebra algebra trigonometry calculus and more

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Web ax 2 bx c 0 cos 4x 4sin 2x 3 0 solve e x 1 over the reals 2 3x 7 4 3x 2 6 5x 9 3 1 x 1 1 x 2 1 x 3 1 x 4 1 Basic Math 52930 67 999 723 1 2 3 4 2 9 2 3 4 2 82 2 212 2 6 7 8 5 1 3 6 7 8 7

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Web Given x 178 1 x 178 2 3x 3 x We have x 1 x 178 x 178 1 x 178 2 x 1 x x 178 1 x 178 2 x 178 1 x 178 2 3x 3 x x 178 1 x 178 2 3 x 1 x x 1 x 178 3 x 1 x x 1 x x 1 x 3 x 1 x x 1 x x 1 x 3
Web Differentiation dxd x 5 3x2 2 Integration 01 xe x2dx Limits x 3lim x2 2x 3x2 9 Solve your math problems using our free math solver with step by step solutions Our math solver supports basic math pre algebra algebra trigonometry calculus and more Web Jun 7 2017 nbsp 0183 32 Explanation Factorise the denominator of the last term by inspection 3 x 2 1 x 1 7 x 2 x 1 We need to get the x s off the denominator to solve I see lots of common terms so to get rid of them multiply both sides of the equation by x 2 x 1 3 x 2 x 1 x 2 1 x 2 x 1 x 1 7 x 2 x 1 x 2 x 1
Web Mar 22 2018 nbsp 0183 32 And now we distribute and combine like terms x4 x3 2x2 3x3 3x2 6x x2 x 2 x4 4x3 6x2 7x 2 That strategy of distributing each term individually works for any polynomial multiplication Answer link x 4 4x 3 6x 2 7x 2 We can think about this as distribution